In AABC, the bisector of ZB meets AC at D. A line PQ|| AC meets AB, BC and BD at P, Q and R respectively. Show that PR X BQ = QR X BP.
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Answered by
3
Answer:
Given △ABC in which BD is the bisector of ∠B and a line PQ||AC meets AB,BC and BD at P,Q and R respectively.
In △BQP, BR is the bisector of ∠B.
∴
BP
BQ
=
PR
QR
⇒ BQ.PR=BP.QR
⇒ PR.BQ=QR.BP [Hence proved]
Answered by
3
Answer:
Given △ABC in which BD is the bisector of ∠B and a line PQ||AC meets AB,BC and BD at P,Q and R respectively.
Proof (i)
In △BQP, BR is the bisector of ∠B.
∴
BP
BQ
=
PR
QR
⇒ BQ.PR=BP.QR
⇒ PR.BQ=QR.BP [Hence proved]
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