Question

In AABC, the perpendicular from A on BC meet
at D such that BD = 7 cm and DC = 12 cm. Find the
ratio of the areas of the triangles ABD and ADC.​

Answer 1

prove that the two triangles are similar. so, we get:

area(ABD)/area(ADC) = (BD/DC)^2 = (7/12)^2 = 49/144

therefore your answer will be 49/144