Question

In AABC, the perpendicular from A on BC meets BC
at D such that BD = 7cm and DC = 12 cm. Find the
ratio of the areas of the triangles ABD and ADC.​

Answer 1

Answer:

In ∆ABD and ∆ADC

angle D = angle D. (90°)

BD = DC (AC bisects BC)

therefore ∆ABD ≈ ∆ADC

BD²/DC² = Ar. of ∆ABD/Ar. of ∆ADC

7²/12²

49/144

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Answer 2

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