Question

In AABC, ZA = 90°, AB = 3 cm, BC = 5 cm and AD 1 BC. Then
the length of AD is​

Answer 1

Answer:

AC^2=5^2-3^2

=25-9=16

AC=√16=4cm

area of triangle ABC=1/2 × 4×3sq cm

=6 sq cm

Now

length of AD=2×area of triangle ABC/base

=2×6/5=2.4cmAns