In AABC, ZB = 45°, ZC = 55° and bisector of ZA meets BC at a point D. Find ZADB and
ZADC.
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Answer:
Explanation:
In triangle ABC
A+B +C =180
A+45+55=180
A=180-100
A=80
AO is the bisector of angle A
then x=y=40
in triangleAOB
x+B+AOB=180
40+45+AOB=180
AOB=95
Similarly in triangleAOC
y+C+AOC=180
40+55+AOC=180
AOC=85
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