IN ∆ AB =AC and Angle A =2x and Angle B =X + 10 .then find measure of all the angles of triangle ABC
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in triangle ABC
AB=AC
so,angle B=angle C
given angle B=x+10
so,angle C will be also x+10
by angle sum property of triangle
2x+x+10+x+10=180
4x+20=180
4x=160
x=40
therefore angle A=2×40=80
angle B=angle C=50
sandhuSaaB1234:
hello ji
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