Question

In ∆ABC
1) BD (Perpendicular) AC then find m<ADB.
2) AN is a median on side BC
if BN=5 then find BC.​​

Answer 1

Given data :

In ∆ ABC 1) BD (Perpendicular) AC then find measure of ∠ ADB. 2) AN is a median on side BC if BN = 5 cm then find BC.

Solution :

1) Here, we know that according to given data, side BD perpendicular to the side AC.

Now, according to defination of perpendicular lines ; {A line is said to be perpendicular to another line if the two lines intersect at a right angle} and we know that right angle is always equal to 90°.

Therefore, ∠ ADB is right angle, hence measure of

∠ ADB = 90°.

2) AN is a median on side BC, BN = 5 cm.

Now,

⟹ BC = BN + NC

Now, definition of median : The median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side in equal parts.

∴ BN = NC Hence, BN = NC = 5 cm

Now,

⟹ BC = BN + NC

⟹ BC = 5 + 5

⟹ BC = 10 cm

Answer : measure of ∠ ADB = 90° and measure of side BC = 10 cm.