Question

In ∆ABC 2∠A-3∠B=6∠C, find ∠A, ∠B, ∠C.​

Answer 1

[I don't really understand the que but I'll try my best <3]

In ∆ABC,

angle A = 3

angle B = 6

angle C = ?

Now,

angle A + angle B + angle C = 180°

=> 3 + 6 + /_C = 180°

=> /_C = (180-9)°

=>/_C = 171°

[its probably wrong :^]