In ABC, 2∠A = 3∠C and ∠A = 30
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find ∠B, ∠C.
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Answer:
2∠A=3∠C
=> 2×30= 3×∠C
=> 60= 3×∠C
=> ∠C= 60÷3
=> ∠C= 20°
∠A+∠B+∠C= 180° (Angle sum property of triangle.)
=> 30°+20°+∠B = 180°
=> 50°+∠B= 180°
=> ∠B= 180-50
=> ∠B = 130°
∠C= 20°
∠B= 130°
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