In ∆ABC, 2 angleA =3 , angle B = 6 , angle C. Calculate angle A, angle B , and angle C
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Answer:
According to the condition in the △ABC, 2∠A=3∠B=6∠C
⇒∠A=3∠C and, ∠B=2∠C
Sum of interior angles of the triangle is 180
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Hence ∠A+∠B+∠C=180
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⇒3∠C+2∠C+∠C=180
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⇒∠C=30
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∴∠A=90
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,∠B=60
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,∠C=30
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