Math, asked by deepalishewale81, 1 month ago

In ∆ABC, √2AC = BC, if sinA=1 sin^2A+sin^2B+sin^2C=2 then what is the value of A, B, C​

Answers

Answered by Durva01
0

Answer:

points A(2, -2), B(8, 4) and C(6, 7) are three vertices of a rectangle ABCD A(- 3, 2) tiv) D(- 2, - 2) Plot these points on a graph paper and hence, find the co-ordinates of its fourth vertex D.

Similar questions