Question

In ∆ABC, 2Angle A =3Angle B =6angle C calculate angle ABC​

Answer 1

Answer:

90°, 60°,30° .

Step-by-step explanation:

2∠A= 3∠B=6∠C= K

∠A= K/2 , ∠B = K/3 , ∠C = K/6

WE KNOW ∠A+∠B+∠C= 180°

=> K/2+K/3+K/6= 180°

=> 6K/6= 180°

=> K= 180°

A= 180°/2 = 90°

B= 180°/3 = 60°

C= 180°/6 = 30°

Answer 2

Answer:

let angle be X

2X = 3B

B = 2/3 X

and also 2X =6C

C = 2/6 X

= 1/3 X

A + B + C =180

X +2/3 X +1/3 X =180

2X =180

X =90° =A

2/3 X = 60° = B

1/3 X = 30° =C

hope it helps