In ∆ABC = 90°, 15 cot A=8.Find
sinA+sinB÷cosA+cosB
Answers
Answered by
0
Step-by-step explanation:
Given,
15cotA=8
cotA=
15
8
=> tanA=
8
15
-------(tanA=
cotA
1
)
We know that,
tanθ=
adjacentSide
oppositeSide
Consider the attached figure, triangleABC
From Pythagoras theorem,
AC
2
=AB
2
+BC
2
AC
2
=8
2
+15
2
=64+225=289
AC=17
cosA=
Hypotenuse
adjacentSide
=
AC
AB
=
17
8
secA=
cosA
1
=
17
8
1
8
17
sinA=
Hypotenuse
oppositeSide
=
AC
BC
=
17
15
Answered by
0
Step-by-step explanation:
answer is 8/15
using Pythagoras theorem I did it.
check the pinned image for solution
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