Question

In ΔABC, A (1, 0), B (K, 0), C (0, 2) and m∠B = π/( 2) then, find the value of K.​

Answer 1

Answer:

We know that the direction ratios of the line segment joining (x

1

,y

1

,z

1

) and (x

2

,y

2

,z

2

) are x

2

−x

1

,y

2

−y

1

,z

2

−z

1

Therefore direction ratios of BA are 3−1,2−4,6−5 i.e., 2,−2,1

a

and direction ratios of BC are 3−1,5−4,3−5 i.e., 2,1,−2

Let m∠ ABC =θ, then cosθ=

2

2

+(−2)

2

+1

2

⋅

2

2

+1

2

+(−2)

2

2×2+−2×1+1×−2

cosθ=

9

−

9

4−2−2

=0

∴θ=90

o

.

Step-by-step explanation:

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