Question

In ∆ABC A(1,2) B(5,5) angle ACB=90°. If Area of ∆ABC is 6.5 square units. Then find the possible number of points for C?

Answer 1

Step-by-step explanation:

In triangle

and angle

degrees. If area of the triangle is

6:⁵

Answer 2

Answer:

C=0

Step-by-step explanation:

Area of ΔABC = $\frac{h^{2} }{2}$sinθcosθ = $\frac{h^{2} }{4}$sin2θ

Maximum Area = $\frac{h^{2} }{4}=\frac{25}{4} =6.25sq.units$

But given Area of ΔABC=6.5

This is impossible

Hence no such points for 'C' exists ⇒Number of possible points for C = 0