in ∆ abc ∆a=100° and ab is equal to AC then find the measure of angle b
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we, know that the sum of all angles of triangle=180
it is given that √a=100
but ,AC=ab
it means it is a isosceles triangle
we also known that angles of equal side is equal
so,
√b =√c
let the √b,√c=X
so,√a +√b +√c =180
so,100+X+X=180
so,2x=180-100=80
so, X=80/2=40
so, √b=40
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