Question

In ∆ABC, √A = 2/3 √B = 3/8 √C . Find all the three angles of ∆ABC.​

Answer 1

Answer:

We know that in a △, the sum of all the interior angles is 180

∘

⇒∠A+∠B+∠C=180

∘

........(1)

Also given that,

∠C=3∠B and 3∠B=2∠A+2∠B

∠A=

2

∠B

Substituting values in (1), we get

2

∠B

+∠B+3∠B=180

∘

∴∠B=40

∘

∠A=20

∘

∠C=120

∘

Explanation:

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