Question

In∆ ABC A (-3,0)
B (3,0)
so find value of (c)​

Answer 1

Given points are A(0,0), B(3,0) and C(3,4).

= > AB^2 = (3 - 0)^2 + (0 - 0)^2 = 9

= > BC^2 = (3 - 3)^2 + (4 - 0)^2 = 16

= > AC^2 = (3 - 0)^2 + (4 - 0)^2 = 25

Here, AB^2 + BC^2 = AC^2.

Therefore, the above vertices are points of right angled triangle.

Answer 2

Step-by-step explanation:

see the answer giiven above.........................................