in ABC , A=3X+1,B=2X,C=2X+4 find x
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Answer:
Step-by-step explanation:
Given, ∠A=x
o
, ∠B=(2x−15)
o
and ∠C=(3x+21)
o
.
We know, by angle sum property, the sum of angles of a triangle is 180
o
.
Then, ∠A+∠B+∠C=180
o
⟹ x
o
+(2x−15)
o
+(3x+21)
o
=180
o
⟹ 6x
o
+6
o
=180
o
⟹ 6x
o
=180
o
−6
o
⟹ 6x
o
=174
o
⟹ x
o
=29
o
.
Therefore,
∠A=x
o
=29
o
,
∠B=(2x−15)
o
=2×29
o
−15
o
=58
o
−15
o
=43
o
and ∠C=(3x+21)
o
=3×29
o
+21
o
=87
o
+21
o
=108
o
.
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