Question

.In ∆ABC ∠A=3x°, ∠B = 2x°, ∠C=x° and AB=12 cm then length of AC=....... *​

Answer 1

Answer:

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Step-by-step explanation:

ANSWER

AC

thus

=

12

2

+5

2

=13

sinA=

AC

BC

=

13

5

tanA=

AB

BC

=

12

5

sinC=

AC

AB

=

13

12

cotC=

AB

BC

=

12

5

Answered By ANSHUL please mark as brainlist please

Answer 2

Answer:

12$\sqrt{3}$  cm ≈ 20.78 cm

Step-by-step explanation:

Given:-

• A ∆ABC in which ∠A=3x°, ∠B = 2x° and ∠C=x°

• AB = 12 cm

To find:-

• Length of AC

Solution:-

In ∆ABC, we have

∠A + ∠B + ∠C = 180°                        [Sum of all the angles of a triangle is 180°]

⇒3x° + 2x° + x° = 180°

⇒6x° = 180°

⇒x° = 30°

Now

∠A = 3x° = 90°

∠B = 2x° = 60°

∠C = x° = 30°

Hence, ∆ABC is a right triangle with ∠A = 90°

⇒ BC is the hypotenuse

tan ∠B = AC / AB

AC = $\frac{AC}{AB}$ × AB

⇒tan ∠B × AB

⇒tan 60° × 12 cm

⇒$\sqrt{3}$ × 12 cm

⇒12$\sqrt{3}$  cm ≈ 20.78 cm

Answer⇒12$\sqrt{3}$  cm ≈ ≈ 20.78 cm

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