Question

In ABC A 50 B 70 and bisector of C meets Ab in d. find the angles of the triangles adc and bdc

Answer 1

In ∆ABC

Angle A = 50°

Angle B = 70°

Angle C = 180°-(50°+70°) = 180° - 130° = 50° .

Now,

As given in Question, D is the bisector if Angle C .

So,

Angle ADC = Angle ADB

Angle ADC+Angle ADB = 50° .

2(Angle ADC )= 50°

Angle ADC = 25° .

Angle ADB = 25° .

#Have A Great Future Ahead !!

Answer 2

Answer:

In ∆ABC

Angle A = 50°

Angle B = 70°

Angle C = 180°-(50°+70°) = 180° - 130° = 50° .

Now,

As given in Question, D is the bisector if Angle C .

So,

Angle ADC = Angle ADB

Angle ADC+Angle ADB = 50° .

2(Angle ADC )= 50°

Angle ADC = 25° .

Angle ADB = 25°

any doubt see in brainly  

answer by K Sanjay