Question

In ∆ABC, ∠A = 50°, ∠B = 60°, arranging the sides of the triangle in ascending order, we get
(a)AB < BC < CA
(b) CA < AB < BC
(c) BC < CA < AB
(d) BC < AB < CA​

Answer 1

Answer:

BC<CA<AB

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Answer 2

Answer:

c

Step-by-step explanation:

C

BC<CA<AB

Using angle sum property in △ABC

∠A+∠B+∠C=180∘⇒50∘+60∘+∠C=180∘⇒∠C=70∘

In any triangle side opposite to the largest angle is the longest side.

Here ∠C is largest and side opposite to it is AB

∴AB is the longest side.

Then comes ∠B and side opposite to it is AC

∴AC is the second longest side.

Then comes ∠A and side opposite to it is AC

∴BC is the shortest side.

So the increasing order of sides is

BC<AC<AB

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