Math, asked by panchalanand51, 6 months ago

. In ∆ABC, ∠A = 60° , ∠B = 70° , find the shortest and the longest side of ∆ABC. there is no figure

Answers

Answered by Anonymous
32

Answer:

to find : shortest angle.

given :

A = 60° -------(1)

B= 70°---------(2)

so,A+B+C=180°

60°+70°+C=180°

130°+C=180°

C=180°-130°

C=50°------(3)

side in front of largest angel is longest &side in front of smallest angle is shortest.

hence,in ABC

shortest side : AB--------from(3)

longest side : AC---------from(2)

Answered by khushi2195
1

Step-by-step explanation:

angle A + angle B + angle C = 180

(angle sum property of a triangle)

let angle C = x

60 + 70 + x = 180

130+x = 180

x= 180 - 130

x = 50

as angle C is the smallest the side opposite to it i.e. side AB is the smallest.

and

as angle B is the largest the side opposite to it i.e. side AC is the longest.

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