Question

In∆ABC, ∠A =60°, ∠B =90°, ∠C =30°,AB = √3cm. AC =-----.
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Answer 1

Answer:

In a right triangle with one angle equal to 30 the side opposing this angle is half of the hypotenuse. If BC opposing this angle is 12 cm then the hypotenuse is 24 cm. Then AB (the other side) is sqrt(24^2–12^2)=20.78 cm (Pythagora). Then the right triangle's area = semi-product of the sides = (12*20.78)/2 = 124.71 cm^2

Answer 2

Answer:

AC = 2 $\sqrt{3}$

Step-by-step explanation:

ABC is a right angled triangle, right angled at B.

Perpendicular = AB

Base = BC

Hypotenuse = AC

Now, sin Ф = p/h

So, sin 30 = AB/AC

or 1/2 = $\sqrt{3}$/  AC

AC = 2 $\sqrt{3}$

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