Question

In ∆ABC ∆A = 70°, ∆B = 2C. find ∆ACD.

Ans:- In ∆ABC

∆A + ∆B + ∆___ = 180 [sum of all angles in triangle]

70+∆B+∆B = 180 [∆B= ∆C]

70+_____ = 180°

2∆B = 180°-______

∆B =_____
_____
2

∆B = ∆C =_____

:.∆ACD =180°

:.∆ACD=______

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Answer 1

Answer:

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