In δabc, ∠a = 90°, ad ┴ bc and ad = bd = 2 cm. the length of cd is
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square of perpendicular =product of segment,
AD² =BD×CD,
2²=2×CD,
4=2×CD,
4/2 =CD,
then
CD=2
AD² =BD×CD,
2²=2×CD,
4=2×CD,
4/2 =CD,
then
CD=2
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