In ∆ABC, ∠A = 90° AD ⊥ BC BD = 5cm DC = 7.2cm then find AD.
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Given : triangle ABC angle a=90°
AD perpendicular BC
BD=5cm DC=7.2cm
To find : AD
Solution:
ΔADB and ΔCDA
∠DBA = ∠DAC ( ∵ each 90° - ∠C)
∠ADB = ∠CDA = 90°
=> ΔADB ≈ ΔCDA ( AA)
AD/CD = BD/AD
=> AD² = BD * CD
=> AD² = 5 * 7.2
=> AD² = 36
=> AD = 6
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