In ∆ ABC , ∠A - ∠B =33° , ∠B - ∠C = 18° , Find the angles of triangle .
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Answer:
It is given that ∠A+∠B=108∘…(1)
We know that the sum of all the angles in a triangle is 180∘.
So we can write it as
∠A+∠B+∠C=180∘
By substituting ∠A+∠B=108∘ in the above equation
108∘+∠C=180∘
On further calculation
∠C=180∘−108∘
By subtraction
∠C=72∘
It is given that ∠B+∠C=130∘
By substituting the value of ∠C
∠B+72∘=130∘
On further calculation
∠B=130∘−72∘
By subtraction
B=58∘
By substituting ∠B=58∘ in equation (1)
So we get
∠A+∠B=108∘
∠A+58∘=108∘
On further calculation
∠A=108∘−58∘
By subtraction
∠A=50∘
Therefore, ∠A=50∘,∠B=58∘ and ∠C=
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