In ∆ABC, ∠A − ∠B = 63°, ∠B − ∠C = 18°.Find the measure of all the angles
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Step-by-step explanation:
we know that sum of all angles =180°
A+B+C=180
given that A-B=63°
B-C=18°
so A=B+63
C=B-18
B+63+B+B-18=180
3B+45=180
3B=180-45
3B=135
B=135/3=45°
so A=B+63=45+63=108°
C=B-18=45-18=27°
so the angles are 108°, 45°, 27°.
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