Question

IN ∆ABC ,≤A = ≤C, AC = 5 and BC = 4. Then find the perimeter of ∆ABC.​


PLEASE SEND CORRECT SOLUTION.

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Answer 1

Answer:

angle A = angle C therefore this angle is right angled triangle angleA=angle C=45 angle B=90 by 45-45-90 therem AB=1/underoot2xAC---(side opposite 45 angle) AB=1/underoot 2x5 AB=5/underoot 2 AB=7.07 perimeter=AB+BC+AC Perimeter=7.07+4+5 perimeter= 16.07