Question

in ∆ABC ∆A is 25° more than ∆B and ∆C is less than ∆B what are the angel of the triangles?​

Answer 1

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Answer 2

Answer:

A = 80°, ∠B = 55° and ∠C = 45°

Step-by-step explanation:

Let ∠A = x + 25°, ∠B = x and ∠C = x - 10°

To find,  the angles of the triangle = ?

We know that,

Sum of anges of triangle = 180°

∴ ∠A + ∠B + ∠C = 180°

⇒ x + 25° + x + x - 10° = 180°

⇒  3x + 15° = 180°

⇒  3x = 180° - 15° = 165°

⇒ x = 55°

∴ x + 25° = 55° + 25° = 80° and

x - 10° = = 55° - 10° = 45°

Hence, ∠A = 80°, ∠B = 55° and ∠C = 45°