In ∆ABC, a line parallel to the side BC intersects the sides AB and AC in
points M and N respectively. AM=8, MB=12, AN=6. Find NC.
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Explanation:
In △APQ and △ABC,
∠A is common.
∠APQ=∠ABC ...[corresponding angles]
∠AQP=∠ACB ...[corresponding angles]
∴△APQ∼△ABC ...(By AAA)
So, once the triangles are similar, their corresponding sides would be proportional.
AB
AP
=
AC
AQ
Hence proved.
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