Question

IN
ABC ~ A POR, A (ABC)
-16, A(PQR)
= 25, then find the value of a ratio
AB
------
PO
​

Answer 1

Answer:

Solution:

Solution:perimeter of∆ABC/perimeter of∆PQR = 1st side of ∆ABC/2nd side of ∆PQR

Solution:perimeter of∆ABC/perimeter of∆PQR = 1st side of ∆ABC/2nd side of ∆PQR35/45=7/9

Solution:perimeter of∆ABC/perimeter of∆PQR = 1st side of ∆ABC/2nd side of ∆PQR35/45=7/9Now , we know that The ratio of two similar triangles are equal to the square of ratio of there corresponding sides

Solution:perimeter of∆ABC/perimeter of∆PQR = 1st side of ∆ABC/2nd side of ∆PQR35/45=7/9Now , we know that The ratio of two similar triangles are equal to the square of ratio of there corresponding sides(7/9) square = 49:81 ans

Step-by-step explanation:

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