Question

In ∆ABC AB =12 BC=16 AC=20 if D is the midpoint of AC then length of BD

Answer 1

(AB+BC+CA)/2=√(BCsq+ADsq)

so 48/2=√(16*16+AD*AD)

or 48*48/4=256+ADsq

so 576-256=AD^2

or 320 =AD sq

so AD=√320=17.888

AD sq - AB sq=BD sq

so 320-144=BDsq

or BD=√176

=13.266