Question

in ∆ABC, AB=12cm, BC=9cm and AD=6cm. (a) find the area of ∆ABC (b) altitude CE​

Answer 1

Answer: Area of ∆ABC  = 27 cm²        

              Altitude CE =4.5cm​

Step-by-step explanation:

Area of triangle = 1/2 x base x height

In ∆ABC, consider BC =  base and AD = height then,

Area of ∆ABC  = 1/2 x 9 x 6

Area of ∆ABC  = 27 cm²        

Now, if we consider AB = base and CE = height then,

Area of ∆ABC = 1/2 x 12 x CE

27 = 6 x CE

CE = 27/6 = 9/2 = 4.5 cm

Altitude CE =4.5cm​

     

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Answer 2

Answer:

we know that the theorem area of rectangle

▪1/2