in abc ab=3.8,ac=3√3,bc=6cm , in rpq rq=7.6cm, pq=12cm ,rp=6√3 find angle p
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PQ=40 using similarity criteria than AB/RQ AC/PR BC/PQ angleA=angle R, angle B=angle Q ,angle C= angle P angle some property of triangle=180, angle A+angle B+angleC=180than C=40 angle C= angle=P
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