In △ABC, AB = 3 and, AC = 4 cm and AD is the bisector of ∠A. Then, BD : DC is
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In ∆ADB & ∆ADC
AD=AD(COMMON)
/_BAD=/_CAD(ANGLE BISECTED)
BD=CD(MEDIAN DIVIDES THE BASE INTO ½)
•: ∆ADB~∆ADC(SSA SIMILARITY)
•: AB/AC=BD/DC(cpst)
3/4=BD:DC
3:4 IS THE ANSWER
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