In ΔABC, AB=3, BC=4, AC=5, then the radius of the circle touching all the three sides is ......,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) 2
(b) 1
(c) 4
(d) 3
Answers
Answered by
4
Option ( b ) is correct .
Explanation :
In ∆ABC ,
AB = c = 3 cm ,
BC = a = 4 cm,
CA = b = 5 cm
We know that ,
( 3 , 4 , 5 ) is a Pythagorean
Triplet .
Therefore ,
∆ABC is a right angled triangle.
CA = b is a hypotenuse .
Now ,
Radius the incircle (r)=( c+a-b)/2
=> r = ( 3 + 4 - 5 )/2
=> r = 2/2 = 1 cm
••••
Answered by
0
Answer:
option b is correct answer
Similar questions
Science,
8 months ago
Math,
1 year ago
Math,
1 year ago
Math,
1 year ago
Social Sciences,
1 year ago