Math, asked by TbiaSupreme, 11 months ago

In ΔABC, AB=3, BC=4, AC=5, then the radius of the circle touching all the three sides is ......,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) 2
(b) 1
(c) 4
(d) 3

Answers

Answered by mysticd
4

Option ( b ) is correct .


Explanation :


In ∆ABC ,


AB = c = 3 cm ,


BC = a = 4 cm,


CA = b = 5 cm


We know that ,


( 3 , 4 , 5 ) is a Pythagorean


Triplet .


Therefore ,


∆ABC is a right angled triangle.


CA = b is a hypotenuse .


Now ,


Radius the incircle (r)=( c+a-b)/2


=> r = ( 3 + 4 - 5 )/2


=> r = 2/2 = 1 cm


••••

Answered by student8116
0

Answer:

option b is correct answer

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