Question

In ∆ABC,AB = 35,AC = 53 and median AM = 4√58. Find r3.​

Answer 1

Let AB be the chord of the given circle with centre O and a radius of 10 cm.

Then AB =16 cm and OB = 10 cm

From O, draw OM perpendicular to AB.

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ BM = (162) cm=8 cm

In the right ΔOMB, we have:

OB2 = OM2 + MB2 (Pythagoras theorem)

⇒ 102 = OM2 + 82

⇒ 100 = OM2 + 64

⇒ OM2 = (100 - 64) = 36

⇒ OM=

√36cm=6 cm

Hence, the distance of the chord from the centre is 6 cm.

HEY MATE IF IT'S HELPFUL TO YOU PLS MARK ME AS BRINLIEST...