in ∆ABC, AB=5 BD=3 and DC=4 find the length of AC
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Given : In triangle ABC AB= 5 , BD = 3 and DC= 4
BD ⊥ AC
To Find : length of AC
Solution:
BD ⊥ AC
=> ΔABD is right angle triangle
Apply Pythagoras theorem
AB² = BD² + AD²
=> 5² = 3² + AD²
=> AD = 4
AC = AD + DC
AC = 4 + 4
=> AC 8
Length of AC = 8
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