In ∆ABC, AB = 5 cm, BC = 8 cm and AC = 10 cm. Then find the smallest and the biggest angle of triangle ABC.
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Given:
AB=5cm
BC=8cm
AC=10cm
To find:
the smallest and biggest angle
Solution:
In any triangle, the angle formed opposite to the longest side is the largest.
In the given triangle, the longest side is AC.
AC=10cm
The angle opposite to the side AC is ∠B.
Hence, ∠B is the largest angle in ΔABC.
In the given triangle, the smallest side is AB.
AB=5cm
The angle opposite to AB is ∠C.
Hence, ∠C is the smallest angle in ΔABC.
Hence, the biggest angle is ∠B and the smallest angle is ∠C.
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