Question

In ∆ABC, AB = 5cm, BC = 6cm and AC = 10cm then find out the value of cos A?

Answer 1

Answer:

1 or 1/2

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

From Cosine rule, we get

a = 6      b = 10     c = 5

Now,

$a^2=b^2+c^2 -2bc cos a$

36 = 100+25 - 2×10×5 cos a

100 cos a =125-36

cos a = $\frac{89}{100}$

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