Math, asked by Keerthan6817, 7 months ago

In ∆ABC, AB = 6 √3 cm, AC = 12 cm and BC = 6 cm. The angle B is : (a) 120° (b) 60° (c) 90° (d) 45°

Answers

Answered by lakshaysoni01279473
2

Answer:

We have,

In ΔABC,

AB=6

3

cm.

AC=12cm.

BC=6cm

Suppose that It is a right angle triangle

Then, We use Pythagoras theorem

(Hypotenuse)

2

=(Height)

2

+(Base)

2

AC

2

=AB

2

+BC

2

12

2

=(6

3

)

2

+6

2

144=108+36

144=144

Hence, It is a right angle triangle.

Then, the angle B is 90

0

Hence, this is the answer.

Answered by sksinghveerrajput809
2

Answer:

We have,

In ΔABC,

AB=6

3

cm.

AC=12cm.

BC=6cm

Suppose that It is a right angle triangle

Then, We use Pythagoras theorem

(Hypotenuse)

2

=(Height)

2

+(Base)

2

AC

2

=AB

2

+BC

2

12

2

=(6

3

)

2

+6

2

144=108+36

144=144

Hence, It is a right angle triangle.

Then, the angle B is 90

0

Hence, this is the answer

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