in ∆abc ab=6 √3cm A=18cm BC=9 FIND THE MEASURE OF ANGLE C
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- ʜᴇʀᴇ , ɪɴ ∆ ᴀʙᴄ , ᴡᴇ ʜᴀᴠᴇ
- ᴀʙ=6√3
- ʙᴄ=9ᴄᴍ
- ᴀᴄ= 18ᴄᴍ
ᴛʜᴇʀᴇꜰᴏʀᴇ ,
ᴀʙ²=(6√3)²=108
ʙᴄ²=9²=81
ꜱɪɴᴄᴇ , 108+81 = 189
ɪ.ᴇ ᴀʙ²+ʙᴄ²=ᴀᴄ²
ᴀɴɢʟᴇ ᴀ= 18ᴄᴍ . ..
. ᴀ-ᴀʙ= ʙ
108-18 = ʙ= 90°
ꜱᴏ ... ᴀ + ʙ + ᴄ = 180°
18+90+ᴄ= 180 °
108-180°= 72 ..
ᴠᴀʟᴜᴇ ᴏꜰ ᴄ = 72°
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