In ∆ ABC, AB = AC, ∠A = 40 degree, find ∠B
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Answer:
Given :-
In ∆ ABC, AB = AC, ∠A = 40°.
To find :- /_ B.
Solution :-
In ∆ABC ,
AB = AC. ...........{Given}
Therefore, /_B = /_C ........{1}
.......(Isosceles triangle theoem}
Let /_B = /_C, be x°............{2}
/_A + /_B + /_C = 180°
......(Angle sum property of triangle)
40° + x° + x° = 180°
2x° = 140°
x. = 70°
/_B = /_C = 70° ........{From 1,2}
Answer :- Angle B is equal to 70°.
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