. In ∆ABC, AB = AC and AD⊥ BC, show that ∆ADB≅∆ADC.
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in Triangle ABC ,Seg ad is perpendicular to seg bc
in Triangle ADB and ADC
angle ADB congurrent angle ADC .......( every 90 degree )
seg AD congurrent seg AD ........( common side )
therefore
TriangleADB and Triangle ADC are congurrent by hypothenus side test
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