Question

.In ∆ABC AB=AC and AD is the median drawn on BC, then ∆ABD ≅∆ACD by which criterion​

Answer 1

Answer:

Answer

Correct option is

A

It is defective to use ∠ABD=∠ACD for proving this result.

△ABD and △ACD

AB=AC  (given )

Then ∠ABD=∠ACD ( because AB=AC )

and  ∠ADB=∠ADC=90( because AD⊥BC )

∴△ABD=△ACD

∠BAD=∠CAD

It is defective to use ∠ABD=∠ACD for proving this result