in △ ABC , AB=AC and AL ⊥ BC Name the altitude and median of △ABC
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In ΔADB and ΔADC
AB−AC (Since ΔABC is an isoscelese triangle )
AD=AD (common)
∠ADB=∠ADC ( since AD is the altitude so each is 90o)
⇒ΔADB≅ΔADC (RHS congruence criterion)
BD=DC (cpct )
⇒AD is the median
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