In ∆ABC,AB=AC and angle A=100 then find angle B
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Answered by
1
Step-by-step explanation:
sum of All angle of triangle is 180
angle A+angle B+angle C =180
100+B+C=180
B+C=180-100
B+C=80
B=C
B+B=80
2×B=80
therefore B=40
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