Question

In ∆abc ,ab=ac and angle b= 50°. find angle a​

Answer 1

Answer:

Step-by-step explanation:

as AB=AC

Hence,

∠B = ∠C = 50°

we know, sum of all angles in a triangle = 180°

Hence,

∠A + ∠B + ∠C = 180°

∠C = 180° - 50° - 50° = 80°

Answer 2

Step-by-step explanation:

In ∆ ABC,

Angle B=Angle C.... (AB=BC)

But Angle B=50°

Therefore,

Angle C=50°

The sum of all angles of triangle is 180°.

Angle A+Angle B+Angle C=180°

Angle A+50°+50°=180°

Angle A+100°=180°

Angle A=180°-100°

Angle A=80°